2. Consider the recurrence relation ak =
2 ak-1 + 15 ak-2 for all integers k2. To find all the sequences of the
form 1, t, t2, t3, ..., tn,... which satisfy this
recurrence relation you need to solve the characteristic equation of the relation. The
characteristic equation of this relation is t2 - 2 · t
- 15 = 0.
By factoring t2 - 2 · t - 15 = (t - 5) (t + 3), so the two values of t which satisfy the characteristic equation are t = 5 and t = -3.
Hence the two sequences which satisfy the recurrence relation ak
= 2 ak-1 + 15 ak-2 for all integers k2 are
1, 5, 25, 125, ..., 5n,... and 1, -3, 9, -27, ..., (-3)n, ...